document.write( "Question 242094: I need help on how to solve a logarithmic Equation. The question is
\n" ); document.write( "3 Log (base 2) x+1 = 7\r
\n" ); document.write( "\n" ); document.write( "When I tried putting this equation into exponential form, I got
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\n" ); document.write( "2^7 = (x+1)^3. However, when I solved for this, I did not end up with
\n" ); document.write( "the answer that is needed. I ended up looking up the answer in the back of the book so that i could see if i could backtrack from there, but it was simply 4.\r
\n" ); document.write( "\n" ); document.write( " Thanks,
\n" ); document.write( " dmc93x@yahoo.com
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Algebra.Com's Answer #177224 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"3%2Alog%282%2C%28x%29%29%2B1=7\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "\"3%2Alog%282%2C%28x%29%29=7-1\" Subtract 1 from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"3%2Alog%282%2C%28x%29%29=6\" Combine like terms.\r
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\n" ); document.write( "\n" ); document.write( "\"log%282%2C%28x%29%29=6%2F3\" Divide both sides by 3.\r
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\n" ); document.write( "\n" ); document.write( "\"log%282%2C%28x%29%29=2\" Reduce\r
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\n" ); document.write( "\n" ); document.write( "\"x=2%5E2\" Convert to exponential form.\r
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\n" ); document.write( "\n" ); document.write( "\"x=4\" Square 2 to get 4.\r
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\n" ); document.write( "\n" ); document.write( "So the solution is \"x=4\"\r
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