document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=242079>Question 242079</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The width of a rectangle is 42 years less than the length. The perimeter of the rectangle is 220 yards. Find the length and width of the rectangle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #177219 by </B><A HREF=/tutors/aboutme.mpl?userid=unlockmath><B>unlockmath(1688)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=unlockmath><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=unlockmath><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=177219\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hello, <BR>\n" );
document.write( "Once we've represented the width and length then we can set up an equation. <BR>\n" );
document.write( "Let x be the length and x-42 be the width. Now we can set up how it will look. <BR>\n" );
document.write( "x+x+(x-42)+(x-42)=220 Combine like terms, we get:<BR>\n" );
document.write( "4x-84=220  Add 84 to both sides to get:<BR>\n" );
document.write( "4x=304 Divide each side by 4 to result in:<BR>\n" );
document.write( "x=76<BR>\n" );
document.write( "Now we know the length is 76 yards and the width is 34 yards. To check it out, add these up. Remember there are 4 sides.<BR>\n" );
document.write( "RJ Toftness<BR>\n" );
document.write( "www.math-unlock.com </SPAN>\n" );
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