document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=242070>Question 242070</A>: <I><SPAN STYLE=\"word-break: break-all;\"> solve for y:<BR>\n" );
document.write( "x+8y= 24<BR>\n" );
document.write( "how do you do these? and<BR>\n" );
document.write( "solve for w: <BR>\n" );
document.write( "4(4-t)=1+w-4 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #177214 by </B><A HREF=/tutors/aboutme.mpl?userid=nyc_function><B>nyc_function(2741)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nyc_function><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nyc_function><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=177214\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> To solve for y means to isolate y on one side of the equation.\r<BR>\n" );
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document.write( "x + 8y = 24\r<BR>\n" );
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document.write( "8y = -x + 24\r<BR>\n" );
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document.write( "y = (-x + 24)/8\r<BR>\n" );
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document.write( "y = (-1/8)(x) + 3\r<BR>\n" );
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document.write( "The same rule applies here.  We isolate w.\r<BR>\n" );
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document.write( "4(4 - t) = 1 + w - 4\r<BR>\n" );
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document.write( "16 - 4t = w - 3\r<BR>\n" );
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document.write( "16 + 3 - 4t = w\r<BR>\n" );
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document.write( "19 - 4t = w\r<BR>\n" );
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document.write( " </SPAN>\n" );
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