document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=242054>Question 242054</A>: <I><SPAN STYLE=\"word-break: break-all;\"> FIND THE BASE AND HEIGHT OF A TRIANGLE<BR>\n" );
document.write( "area=60sq units  base= 3x+6  height= x+5   <BR>\n" );
document.write( "area=1/2 bh   help??? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #177206 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=177206\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> FIND THE BASE AND HEIGHT OF A TRIANGLE<BR>\n" );
document.write( "area=60sq units base= 3x+6 height= x+5 <BR>\n" );
document.write( "---------<BR>\n" );
document.write( "Area = (1/2)bh<BR>\n" );
document.write( "60 = (1/2)(3x+6)(x+5)<BR>\n" );
document.write( "(3x+6)(x+5) = 120<BR>\n" );
document.write( "3x^2 + 15x + 6x + 30 = 120<BR>\n" );
document.write( "3x^2 + 21x - 90 = 0<BR>\n" );
document.write( "x^2 + 7x - 30 = 0<BR>\n" );
document.write( "---<BR>\n" );
document.write( "x = [-7 +- sqrt(49 - 4*-30)]/2<BR>\n" );
document.write( "---<BR>\n" );
document.write( "x = [-7 +- sqrt(169)]/2<BR>\n" );
document.write( "Positive Solution:<BR>\n" );
document.write( "x = (-7 + 13]/2<BR>\n" );
document.write( "x = 3<BR>\n" );
document.write( "---<BR>\n" );
document.write( "base = 3x+6 = 3*3+6 = 15 units<BR>\n" );
document.write( "height = x+5 = 3+5 = 8 units<BR>\n" );
document.write( "=================================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );