document.write( "Question 241922: You ride your bike to campus a distance of 5 miles and return home on the same route. Going to campus, you average 9 mph faster than on your return trip home. If the round trip takes one hour and ten minutes, what is your average rate on the return trip? \n" ); document.write( "
Algebra.Com's Answer #177205 by ankor@dixie-net.com(22740)\"\" \"About 
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You ride your bike to campus a distance of 5 miles and return home on the same route.
\n" ); document.write( "Going to campus, you average 9 mph faster than on your return trip home.
\n" ); document.write( " If the round trip takes one hour and ten minutes, what is your average rate on the return trip?
\n" ); document.write( ":
\n" ); document.write( "let s = speed on the return trip
\n" ); document.write( "then
\n" ); document.write( "(s+9) = speed to the campus
\n" ); document.write( ":
\n" ); document.write( "Write a time equation: Time = dist/speed
\n" ); document.write( "Change time to a fraction 1\"1%2F6\" = \"7%2F6\" hrs
\n" ); document.write( ":
\n" ); document.write( "\"5%2Fs\" + \"5%2F%28s%2B9%29\" = \"7%2F6\"
\n" ); document.write( "Multiply equation by 6s(s+9), results
\n" ); document.write( "6(s+9)*5 + 6s(5) = s(s+9)*7
\n" ); document.write( ":
\n" ); document.write( "5(6s+54) + 30s = 7(s^2 + 9s)
\n" ); document.write( ":
\n" ); document.write( "30s + 270 + 30s = 7s^2 + 63s
\n" ); document.write( "Arrange as a quadratic equation
\n" ); document.write( "0 = 7s^2 + 63s - 60s - 270
\n" ); document.write( ":
\n" ); document.write( "7s^2 + 3s - 270 = 0
\n" ); document.write( "Factors to:
\n" ); document.write( "(7s + 45)(s - 6) = 0
\n" ); document.write( "The positive solution
\n" ); document.write( "s = 6 mph on the return trip
\n" ); document.write( ";
\n" ); document.write( ";
\n" ); document.write( "Check this by finding the times
\n" ); document.write( "5/6 + 5/15 = 1.667; which is 1 hr 10 min
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