document.write( "Question 241922: You ride your bike to campus a distance of 5 miles and return home on the same route. Going to campus, you average 9 mph faster than on your return trip home. If the round trip takes one hour and ten minutes, what is your average rate on the return trip? \n" ); document.write( "
Algebra.Com's Answer #177205 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! You ride your bike to campus a distance of 5 miles and return home on the same route. \n" ); document.write( "Going to campus, you average 9 mph faster than on your return trip home. \n" ); document.write( " If the round trip takes one hour and ten minutes, what is your average rate on the return trip? \n" ); document.write( ": \n" ); document.write( "let s = speed on the return trip \n" ); document.write( "then \n" ); document.write( "(s+9) = speed to the campus \n" ); document.write( ": \n" ); document.write( "Write a time equation: Time = dist/speed \n" ); document.write( "Change time to a fraction 1 \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( "Multiply equation by 6s(s+9), results \n" ); document.write( "6(s+9)*5 + 6s(5) = s(s+9)*7 \n" ); document.write( ": \n" ); document.write( "5(6s+54) + 30s = 7(s^2 + 9s) \n" ); document.write( ": \n" ); document.write( "30s + 270 + 30s = 7s^2 + 63s \n" ); document.write( "Arrange as a quadratic equation \n" ); document.write( "0 = 7s^2 + 63s - 60s - 270 \n" ); document.write( ": \n" ); document.write( "7s^2 + 3s - 270 = 0 \n" ); document.write( "Factors to: \n" ); document.write( "(7s + 45)(s - 6) = 0 \n" ); document.write( "The positive solution \n" ); document.write( "s = 6 mph on the return trip \n" ); document.write( "; \n" ); document.write( "; \n" ); document.write( "Check this by finding the times \n" ); document.write( "5/6 + 5/15 = 1.667; which is 1 hr 10 min \n" ); document.write( " \n" ); document.write( " |