document.write( "Question 241833: sqrt(4x-5) = sqrt(x+9)\r
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document.write( "sqrt(x+49) + 7=x\r
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document.write( "Each time that I tried to solve these two (seperate) problems....kept getting an answer that does not make any sense....I think that I am doing something wrong but not sure where I am screwing it up. Can someone show me what I am doing wrong?- thank you. \n" );
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Algebra.Com's Answer #177117 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! sqrt(4x-5) = sqrt(x+9) \n" ); document.write( "--- \n" ); document.write( "Square both sides to get: \n" ); document.write( "4x-4 = x+9 \n" ); document.write( "3x = 13 \n" ); document.write( "x = 13/3 \n" ); document.write( "-------------------------------- \r \n" ); document.write( "\n" ); document.write( "sqrt(x+49) + 7=x \n" ); document.write( "sqrt(x+49) = x-7 \n" ); document.write( "Square both sides to get: \n" ); document.write( "x+49 = x^2-14x+49 \n" ); document.write( "x^2 -15x = 0 \n" ); document.write( "x(x-15) = 0 \n" ); document.write( "x = 0 or x = 15 \n" ); document.write( "------------ \n" ); document.write( "Checking for extraneous roots: \n" ); document.write( "Can x = 0 ? \n" ); document.write( "sqrt(0+49)+7 = 0 \n" ); document.write( "7+7 = 0 \n" ); document.write( "false \n" ); document.write( "--- \n" ); document.write( "Can x = 15 ? \n" ); document.write( "sqrt(15+49) +7 = 15 \n" ); document.write( "sqrt(64)+7 = 15 \n" ); document.write( "8+7 = 15 \n" ); document.write( "true \n" ); document.write( "======== \n" ); document.write( "Only solution: x = 15 \n" ); document.write( "============================== \n" ); document.write( "Cheers, \n" ); document.write( "stan H. \n" ); document.write( "-------------------- \n" ); document.write( " \n" ); document.write( " |