document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=241824>Question 241824</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the perimeter of a rectangle is 88 feet. the length of the rectangle is 4 feet longer than three times the width. find the dimensions of the rectangle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #177109 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=177109\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> L=3W+4<BR>\n" );
document.write( "2L+2W=88<BR>\n" );
document.write( "2(3W+4)+2W=88<BR>\n" );
document.write( "6W+8+2W=88<BR>\n" );
document.write( "8W=88-8<BR>\n" );
document.write( "8W=80<BR>\n" );
document.write( "W=80/8<BR>\n" );
document.write( "W=10 FT. FOR THE WIDTH <BR>\n" );
document.write( "L=3*10+4=30+4=34 FT. FOR THE LENGTH.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "2*34+2*10=88<BR>\n" );
document.write( "68+20=88<BR>\n" );
document.write( "88=88 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );