document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=241750>Question 241750</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two angles are complementary. Twice one angle plus the other is 143 degrees. Find the measure of each angle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #177091 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=177091\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x+y=90 or y=90-x<BR>\n" );
document.write( "2x+y=143<BR>\n" );
document.write( "2x+90-x=143<BR>\n" );
document.write( "x=143-90<BR>\n" );
document.write( "x=53 ans.<BR>\n" );
document.write( "y=90-53=37 ans.<BR>\n" );
document.write( "Proof:<BR>\n" );
document.write( "2*53+37=143<BR>\n" );
document.write( "106+37=143<BR>\n" );
document.write( "143=143 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );