document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=30960>Question 30960</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0131492594/algebrahomeworkh>Introductory and Intermediate Algebra</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> Factor completely <BR>\n" );
document.write( "5x^2 - 6xy - 8y^2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #17707 by </B><A HREF=/tutors/aboutme.mpl?userid=ikdeep><B>ikdeep(226)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ikdeep><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ikdeep><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=17707\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 5x^2 - 6xy - 8y^2\r<BR>\n" );
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document.write( "(Here you must know how we make factors i.e. splitting of the middle term...if you might not know then please contact me again and I will explain to you... )\r<BR>\n" );
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document.write( "= 5x^2 - (10-4)xy - 8y^2\r<BR>\n" );
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document.write( "= 5x^2 -10xy + 4xy - 8y^2\r<BR>\n" );
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document.write( "taking common from first two i.e. 5x^2 -10xy and last two i.e. 4xy - 8y^2<BR>\n" );
document.write( "variables...we get \r<BR>\n" );
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document.write( "= 5x(x-2y) + 4y(x-2y)\r<BR>\n" );
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document.write( "= (5x + 4y)(x-2y)...........\r<BR>\n" );
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document.write( "hope this will help you \r<BR>\n" );
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document.write( "Please feel free to revert back for any further queries.<BR>\n" );
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document.write( " </SPAN>\n" );
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