document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=241679>Question 241679</A>: <I><SPAN STYLE=\"word-break: break-all;\"> hi, i tried solving this system and it just confuses me so much.\r<BR>\n" );
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document.write( "1/a + 1/b - 2/c = 9<BR>\n" );
document.write( "3/a - 2/b + 1/c + -1<BR>\n" );
document.write( "2/a - 1/b + 3/c = 7\r<BR>\n" );
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document.write( "i tried modifying it to <BR>\n" );
document.write( "a + b - 2c = 9<BR>\n" );
document.write( "3a - 2b + c = -1<BR>\n" );
document.write( "2a - b + 3c + 7\r<BR>\n" );
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document.write( "i tried moving the variables into the numerator and switching the signs after i did that but it doesnt seem to work because i eliminated and substituted and the triplet i got was (65, 119, 29)<BR>\n" );
document.write( " so please help me  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #177068 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=177068\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The first thing you did wrong is eliminate the numerators.<BR>\n" );
document.write( "a + b - 2c = 9<BR>\n" );
document.write( "3a - 2b + c = -1<BR>\n" );
document.write( "2a - b + 3c + 7<BR>\n" );
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document.write( "You need to eliminate one of the terms. <BR>\n" );
document.write( "1/a+1/b-2/c=9 add this equation to the third equation<BR>\n" );
document.write( "3/a-2/b+1/c[=]-1<BR>\n" );
document.write( "2/a-1/b+3/c=7<BR>\n" );
document.write( "1/a+1/b-2/c=9<BR>\n" );
document.write( "-------------------<BR>\n" );
document.write( "3/a+1/c=16 #  now subtract equation 2<BR>\n" );
document.write( "-3a+2/b-1/c=+1<BR>\n" );
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document.write( "2/b=17<BR>\n" );
document.write( "17b=2<BR>\n" );
document.write( "b=2/17 ans.<BR>\n" );
document.write( "1/a+1/(2/17)-2/c=9<BR>\n" );
document.write( "1/a+1*17/2-2/c=9<BR>\n" );
document.write( "1/a-2/c=9+17/2<BR>\n" );
document.write( "1/a-2/c=18/2-17/2<BR>\n" );
document.write( "1/a-2/c=1/2 multiply the equation marked with a # by 2 & add.<BR>\n" );
document.write( "6/a+2/c=32<BR>\n" );
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document.write( "7/a=31.5<BR>\n" );
document.write( "32.5a=7<BR>\n" );
document.write( "a=7/32.5<BR>\n" );
document.write( "a=14/65 ans.<BR>\n" );
document.write( "2/(14/65)-1/(2/17)+3/c=7<BR>\n" );
document.write( "2*65/14-1*17/2+3/c=7<BR>\n" );
document.write( "130/14-17/2+3/c=7<BR>\n" );
document.write( "3/c=7-130/14+17/2<BR>\n" );
document.write( "3/c=(98-130+119)/14<BR>\n" );
document.write( "3/c=87/14<BR>\n" );
document.write( "87c=3*14<BR>\n" );
document.write( "87c=42<BR>\n" );
document.write( "c=42/87<BR>\n" );
document.write( "c=14/29 ans.<BR>\n" );
document.write( "I'll leave the proof up to you. </SPAN>\n" );
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