document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=241679>Question 241679</A>: <I><SPAN STYLE=\"word-break: break-all;\"> hi, i tried solving this system and it just confuses me so much.\r<BR>\n" );
document.write( "\n" );
document.write( "1/a + 1/b - 2/c = 9<BR>\n" );
document.write( "3/a - 2/b + 1/c + -1<BR>\n" );
document.write( "2/a - 1/b + 3/c = 7\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "i tried modifying it to <BR>\n" );
document.write( "a + b - 2c = 9<BR>\n" );
document.write( "3a - 2b + c = -1<BR>\n" );
document.write( "2a - b + 3c + 7\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "i tried moving the variables into the numerator and switching the signs after i did that but it doesnt seem to work because i eliminated and substituted and the triplet i got was (65, 119, 29)<BR>\n" );
document.write( " so please help me  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #177061 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=177061\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> multiply 1st eqn by -3 and add to 2nd eqn ___ -5/b + 7/c = -28 (I)\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "multiply 1st eqn by -2 and add to 3rd eqn ___ -3/b + 7/c = -11 (II)\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "subtract eqn (I) from (II) ___ 2/b = 17 ___ 2/17 = b\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "substituting ___ -3/(2/17) + 7/c = -11\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "-51/2 + 7/c = -11 ___ 7/c = 29/2 ___ c = 14/29\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "substituting ___ 1/a + 1/(2/17) - 2/(14/29) = 9 ___ 1/a + 17/2 - 58/14 = 9\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "1/a + 119/14 - 58/14 = 126/14 ___ 1/a = 65/14\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "a = 14/65 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );