document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=241681>Question 241681</A>: <I><SPAN STYLE=\"word-break: break-all;\"> determine the length of the sides of a cube who's interior DIAGONALS measure 173mm. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #177042 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=177042\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A right triangle with one leg=x, the other leg=xsqrt2 & a hypotenuse=173<BR>\n" );
document.write( "x^2+(xsqrt2)^2=173<BR>\n" );
document.write( "x^2+2x^2=173<BR>\n" );
document.write( "3x^2=173<BR>\n" );
document.write( "x^2=173/3<BR>\n" );
document.write( "x^2=57.6667<BR>\n" );
document.write( "x=sqrt57.6667<BR>\n" );
document.write( "x=7.594 ans. for the diagonal.<BR>\n" );
document.write( "Proof:<BR>\n" );
document.write( "7.594^2+7.594^2*2=173<BR>\n" );
document.write( "57.6667+57.6667*2=173<BR>\n" );
document.write( "57.6667+115.333=173<BR>\n" );
document.write( "173=173<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );