document.write( "Question 30976: Joe has $40,000 to invest. He invests part of it at 5%, one-fourth of this amount at 6%, and the rest of the money at 7%. His total annual interest income is $2,530. Find the amount invested at each rate. \n" ); document.write( "
Algebra.Com's Answer #17701 by blubunny01(20)\"\" \"About 
You can put this solution on YOUR website!
Let's first define three variables to keep track of the amounts invested at each rate.\r
\n" ); document.write( "\n" ); document.write( "x = amount invested at 5%
\n" ); document.write( "y = amount invested at 6%
\n" ); document.write( "z = amount invested at 7%\r
\n" ); document.write( "\n" ); document.write( "This problem has three unknown values - let's establish the relationships between these unknowns.\r
\n" ); document.write( "\n" ); document.write( "We know that the amount invested at 6% (y) is 1/4 the amount invested at 5% (x). Therefore, we can say:
\n" ); document.write( "\"y+=+%281%2F4%29%2Ax\"\r
\n" ); document.write( "\n" ); document.write( "Then, whatever is not invested at 5% or 6% will be invested at 7%. The total amount of money Joe is investing is $40,000. So, we can say:
\n" ); document.write( "\"z+=+40000+-+x+-+y\" (to find the \"rest of the money\" invested at 7%)
\n" ); document.write( " or...\r
\n" ); document.write( "\n" ); document.write( "\"z+=+40000+-+x+-+%281%2F4%29%2Ax\" (substituting the y equation we created earlier)\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "We know his total annual interest income is $2,530. To find the income, we just take the amounts invested at each rate and multiply them by their respective rates (i.e. since x is the amount invested at 5%, we find the interest income by multiplying 0.05x). This means:\r
\n" ); document.write( "\n" ); document.write( "\"0.05%2Ax+%2B+0.06%2Ay+%2B+0.07%2Az+=+2530\"\r
\n" ); document.write( "\n" ); document.write( " or...\r
\n" ); document.write( "\n" ); document.write( "\"0.05%2Ax+%2B+0.06%2A%281%2F4%29%2Ax+%2B+0.07%2A%2840000+-+x+-+%281%2F4%29%2Ax%29+=+2530\"\r
\n" ); document.write( "\n" ); document.write( "Now, solve for x:\r
\n" ); document.write( "\n" ); document.write( "\"0.05%2Ax+%2B+0.015%2Ax+%2B+0.07%2840000+-+1.25%2Ax%29+=+2530\" [simplify equation]\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"0.05%2Ax+%2B+0.015%2Ax+%2B+0.07%2840000+-+1.25%2Ax%29+=+2530\" [simplify equation]\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"0.065%2Ax+%2B+2800+-+0.0875%2Ax+=+2530\" [more simplifying the equation]\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"2800+-+0.0225%2Ax+=+2530\" [combine like terms]\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"-0.0225%2Ax+=+-+270\" [combine like terms]\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x+=+12%2C000\" [divide both sides by -0.0225 to isolate x]\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Going back to our original equations:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "x = amount invested at 5%
\n" ); document.write( "y = amount invested at 6% = (1/4)x
\n" ); document.write( "z = amount invested at 7% = 40,000 - x - y\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "We have x = 12,000.
\n" ); document.write( "y = (1/4)(12,000) = 3,000.
\n" ); document.write( "z = 40,000 - 12,000 - 3,000 = 25,000.
\n" ); document.write( "
\n" );