document.write( "Question 27948: the perimater of a rectangle is 56 cm. the lenth of the rectangle is 2 cm more than the width find the dimensions of the rectangle \n" ); document.write( "
Algebra.Com's Answer #17700 by blubunny01(20)\"\" \"About 
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If you draw a rectangle and label the length (L) and width (W), you will see that the perimeter is the sum of all the sides, i.e.
\n" ); document.write( "\"P+=+L+%2B+W+%2B+L+%2B+W\"
\n" ); document.write( "\"P+=+2L+%2B+2W\"\r
\n" ); document.write( "\n" ); document.write( "Now, let's set W = x. Then, since the length is 2cm longer than the width, we can say L = x+2.
\n" ); document.write( "We also know that the perimeter is 56cm.
\n" ); document.write( "So, plugging these new equations into our original equation, we have:\r
\n" ); document.write( "\n" ); document.write( "\"P+=+2L+%2B+2W\"
\n" ); document.write( "\"56+=+2%28x%2B2%29+%2B+2x\"\r
\n" ); document.write( "\n" ); document.write( "Now, we can solve this equation for x.\r
\n" ); document.write( "\n" ); document.write( "\"56+=+2x+%2B+4+%2B+2x\" [distribute the 2 to the tokens within the parentheses]\r
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\n" ); document.write( "\n" ); document.write( "\"56+=+4x+%2B+4\" [combine like terms]\r
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\n" ); document.write( "\n" ); document.write( "\"52+=+4x\" [subtract 4 on both sides]\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"13+=+x\" [divide both sides by 4 to isolate x]\r
\n" ); document.write( "\n" ); document.write( "So, to get the dimensions, we go back to the equations we wrote:
\n" ); document.write( "W = x.
\n" ); document.write( "L = x+2. \r
\n" ); document.write( "\n" ); document.write( "So, the width is 13cm, and the length is 15cm.
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