document.write( "Question 27948: the perimater of a rectangle is 56 cm. the lenth of the rectangle is 2 cm more than the width find the dimensions of the rectangle \n" ); document.write( "
Algebra.Com's Answer #17700 by blubunny01(20)![]() ![]() ![]() You can put this solution on YOUR website! If you draw a rectangle and label the length (L) and width (W), you will see that the perimeter is the sum of all the sides, i.e. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now, let's set W = x. Then, since the length is 2cm longer than the width, we can say L = x+2. \n" ); document.write( "We also know that the perimeter is 56cm. \n" ); document.write( "So, plugging these new equations into our original equation, we have:\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now, we can solve this equation for x.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So, to get the dimensions, we go back to the equations we wrote: \n" ); document.write( "W = x. \n" ); document.write( "L = x+2. \r \n" ); document.write( "\n" ); document.write( "So, the width is 13cm, and the length is 15cm. \n" ); document.write( " |