document.write( "Question 241624: Raleigh has a total of 54 coins, all of which are either dimes or nickels. The total value is $4.30. Find the number of each type of coin. \n" ); document.write( "
Algebra.Com's Answer #176984 by kelli_scofield(5)\"\" \"About 
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I am going to set this problem up with two equations.\r
\n" ); document.write( "\n" ); document.write( "Equation 1:
\n" ); document.write( "n+d=54\r
\n" ); document.write( "\n" ); document.write( "Equation 2:
\n" ); document.write( ".05n+.10d=4.30\r
\n" ); document.write( "\n" ); document.write( "The first equation signifies the number of coins. n=nickels and d=dimes.
\n" ); document.write( "The second equation signifies the worth of the coins.\r
\n" ); document.write( "\n" ); document.write( "First, I am going to make equation #2 simpler by moving the decimal place on each term two units to the right. My new equation number 2 is 5n+10d=430\r
\n" ); document.write( "\n" ); document.write( "Now, the two equations are:
\n" ); document.write( "(Equation 1)n+d=54
\n" ); document.write( "(Equation 2)5n+10d=430\r
\n" ); document.write( "\n" ); document.write( "Using elimination, I am going to multiply equation #1 by -5(negative 5).
\n" ); document.write( "This gives me:
\n" ); document.write( "(Equation 1)-5n-5d=-270
\n" ); document.write( "(Equation 2) 5n+10d=430\r
\n" ); document.write( "\n" ); document.write( "Adding the two equations, the n's get cancelled.
\n" ); document.write( "Now you have one equation of:
\n" ); document.write( "5d=160\r
\n" ); document.write( "\n" ); document.write( "Dividing the equation by 5 gives you: d=32\r
\n" ); document.write( "\n" ); document.write( "Plug (32) for d in one of the original equations.
\n" ); document.write( "n+d=54
\n" ); document.write( "n+(32)=54\r
\n" ); document.write( "\n" ); document.write( "After subtracting 32, you get n=22.\r
\n" ); document.write( "\n" ); document.write( "So, your answer is 22 nickels and 32 dimes.\r
\n" ); document.write( "\n" ); document.write( "You can check your answer by plugging both of these values in for each of the original equations.
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