document.write( "Question 241039: brandon is 10 years older than brian. in 2 years Brandon will be 3 times as old as Brian. How old are they now? \n" ); document.write( "
Algebra.Com's Answer #176980 by College Student(505)\"\" \"About 
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Since Brandon is ten years older than Brian, let:
\n" ); document.write( "Brian = x
\n" ); document.write( "Brandon = x+10
\n" ); document.write( ".
\n" ); document.write( "In 2 years Brandon will be 3 times as old as Brian, so our equation now becomes:
\n" ); document.write( "\"%28x%2B10%29%2B2=3%28x%2B2%29\"
\n" ); document.write( "Now solve for x to determine Brian's age.
\n" ); document.write( "\"x%2B12=3x%2B%283%2A2%29\"
\n" ); document.write( "\"x%2B12=3x%2B6\"
\n" ); document.write( "\"12-6=3x-x\"
\n" ); document.write( "\"6=2x\"
\n" ); document.write( "\"x=6%2F2\"
\n" ); document.write( "\"x=3\" ...this is Brian's age (today)
\n" ); document.write( ".
\n" ); document.write( "\"x%2B10=3%2B10=13\" ...this is Brandon's age (today).
\n" ); document.write( ".
\n" ); document.write( "Let's plug in the x value in the original equation to see if it makes sense.
\n" ); document.write( "Remember: \"%28x%2B10%29%2B2=3%28x%2B2%29\"
\n" ); document.write( "\"%283%2B10%29%2B2=3%283%2B2%29\"
\n" ); document.write( "\"13%2B2=3%283%2B2%29\"
\n" ); document.write( "\"15=3%285%29\"
\n" ); document.write( "\"15=15\"
\n" ); document.write( ".
\n" ); document.write( "The answer checks! We're done! :)
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