document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=241497>Question 241497</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Rachel has $20,000 to invest. She plans to invest part at 5%, with the remainder invested at 6%. Find the amount invested at each rate if the total annual interest income is $1060 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #176941 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=176941\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .06x+.05(20,000-x)=1,060<BR>\n" );
document.write( ".06x+1,000-.05x=1,060<BR>\n" );
document.write( ".01x=1,060-1,000<BR>\n" );
document.write( ".01x=60<BR>\n" );
document.write( "x=60/.01<BR>\n" );
document.write( "x=6,000 invested @ 6%<BR>\n" );
document.write( "20,000-6,000=14,000 invested @ 55<BR>\n" );
document.write( "Proof:<BR>\n" );
document.write( ".06*6,000+.05*14,000=1,060<BR>\n" );
document.write( "360+700=1,060<BR>\n" );
document.write( "1,060=1,060 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );