document.write( "Question 241512: Part of $20,000 is invested at 12% interest. The rest is invested at 8% interest. The total interest fro the two accounts is $1,800. How much money was invested at each rate? \n" ); document.write( "
Algebra.Com's Answer #176934 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! .12x+.08(20,000-x)=1,800 \n" ); document.write( ".12x+1600-.08x=1,800 \n" ); document.write( ".04x=1,800-1,600 \n" ); document.write( ".04x=200 \n" ); document.write( "x=200/.04 \n" ); document.write( "x=5,000 invested @ 12%. \n" ); document.write( "20,000-5,000=15,000 invested @ 8% \n" ); document.write( "Proof: \n" ); document.write( ".12*5,000+.08*15,000=1,800 \n" ); document.write( "600+1,200=1,800 \n" ); document.write( "1,800=1,800 \n" ); document.write( " |