document.write( "Question 241532: how many gallons of a mixture containing 80% alcohol should be added to 6 gallons of a 25% solution togive 30% solution? \n" ); document.write( "

Algebra.Com's Answer #176931 by checkley77(12844) $\"\"$ $\"About$

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.80x+.25*6=.30(6+x)
\n" ); document.write( ".80x+1.5=1.8+.30x
\n" ); document.write( ".80x-.30x=1.8-1.5
\n" ); document.write( ".5x=.3
\n" ); document.write( "x=.3/.5
\n" ); document.write( "x=.6 gal. of 80% mixture is used.
\n" ); document.write( "Proof:
\n" ); document.write( ".80*.6+.25*6=.30(6+.6)
\n" ); document.write( ".48+1.5=.30*6.6
\n" ); document.write( "1.98=.3*1.6
\n" ); document.write( "1.98=1.98
\n" ); document.write( " \n" ); document.write( "

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