document.write( "Question 241553: a fulcrum is placed under the center of a board. in order for two objects to balance on the board, the distance (in feet ) of each object from the center of the board must vary inversely with its weight (in pounds) . what is the distance of each object from the center of the board ? \r
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\n" ); document.write( "\n" ); document.write( " (7.5 lb)a___________5ft______b (12.5 lb)
\n" ); document.write( "the distance between two objects is 5ft\r
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Algebra.Com's Answer #176919 by checkley77(12844)\"\" \"About 
You can put this solution on YOUR website!
7.5x=12.5(5-x)
\n" ); document.write( "7.5x=62.5-12.5x
\n" ); document.write( "7.5x+12.5x=62.5
\n" ); document.write( "20x=62.5
\n" ); document.write( "x=62.5/20
\n" ); document.write( "x=3.125 is the distandce of the 7.5 pound item from the center.
\n" ); document.write( "5-3.175=1.875 is the distance of the 12.5 pound weight from the center.
\n" ); document.write( "Proof:
\n" ); document.write( "7.5*3.125=12.5*1.875
\n" ); document.write( "23.4375=23.4375
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