document.write( "Question 241558: If I run my first 60 km lap at a rate 25% faster than my usual 12 km/hr, and my second 60 km lap at a rate ___% slower than 12 km/hr, then my overall average speed will be my usual speed\r
\n" ); document.write( "\n" ); document.write( "A) 50/3 B) 20 C) 25 D) 250/3
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Algebra.Com's Answer #176914 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
Usual speed is 12 km/hr
\n" ); document.write( "25% faster = 12 + .25*12 = 12*(1+.25) = 12*(1.25) = 15 km/hr
\n" ); document.write( "25% slower = 12 - x*12 = 12*(1-x) km/hr\r
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\n" ); document.write( "\n" ); document.write( "first 60 km lap is done at 15 km/hr
\n" ); document.write( "second 60 km lap is done at 12*(1-x) km/hr\r
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\n" ); document.write( "\n" ); document.write( "overall average is 12km /hr\r
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\n" ); document.write( "\n" ); document.write( "15 * 60 + 12*(1-x) * 60 = 120 * 12\r
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\n" ); document.write( "\n" ); document.write( "900 + (12-12x) * 60 = 1440\r
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\n" ); document.write( "\n" ); document.write( "900 + 720 - 720*x = 1440\r
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\n" ); document.write( "\n" ); document.write( "add 720*x to both sides of the equation and subtract 1440 from both sides to get:\r
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\n" ); document.write( "\n" ); document.write( "900 + 720 - 1440 = 720*x\r
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\n" ); document.write( "\n" ); document.write( "combine like terms to get:\r
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\n" ); document.write( "\n" ); document.write( "1620 - 1440 = 720*x\r
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\n" ); document.write( "\n" ); document.write( "combine further to get:\r
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\n" ); document.write( "\n" ); document.write( "180 = 720*x\r
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\n" ); document.write( "\n" ); document.write( "divide both sides of the equation by 720 to get:\r
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\n" ); document.write( "\n" ); document.write( "x = .25\r
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\n" ); document.write( "\n" ); document.write( "substitute in the original equation to get:\r
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\n" ); document.write( "\n" ); document.write( "15 * 60 + 12*(1-x) * 60 = 120 * 12 becomes:\r
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\n" ); document.write( "\n" ); document.write( "15*60 + 12*(1-.25)*60 = 120*12 which becomes:\r
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\n" ); document.write( "\n" ); document.write( "900 + 12*.75*60 = 1440 which becomes\r
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\n" ); document.write( "\n" ); document.write( "900 + 540 = 1440 which becomes:\r
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\n" ); document.write( "\n" ); document.write( "1440 = 1440 which confirms the answer is good.\r
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\n" ); document.write( "\n" ); document.write( "answer is:\r
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\n" ); document.write( "\n" ); document.write( "x = .25 * 100% = 25%\r
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