document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=30978>Question 30978</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Coffee Company blends coffee type A worth $0.93 per pound with coffee type B worth $1.20 per pound to get 30 pounds of a coffee blen worth $1.02 per pound.  How many pounds of each type of coffee does the company use? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #17690 by </B><A HREF=/tutors/aboutme.mpl?userid=Paul><B>Paul(988)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Paul><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=17690\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the mixture for $0.93 be x<BR>\n" );
document.write( "Let the mixture for $1.2 be y<BR>\n" );
document.write( "x+y=30<BR>\n" );
document.write( "and y=30-x (subsitution)<BR>\n" );
document.write( "0.93x+1.2y=1.02(30)<BR>\n" );
document.write( "0.93x+1.2(30-x)=30.6<BR>\n" );
document.write( "0.93x-1.2x=30.6-36<BR>\n" );
document.write( "-0.27x=-5.4<BR>\n" );
document.write( "x=20\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "y=30-20<BR>\n" );
document.write( "y=10<BR>\n" );
document.write( "<font color = red>HEnce, the mixture for $0.93 is 20pounds and the mixture for $1.2 is 10 pounds.</font><BR>\n" );
document.write( "Paul. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );