document.write( "Question 241517: The height about the ground of an object t seconds after it is launched vertically upward is h(t)=100t-5t^2 meters
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document.write( "What is the velocity of the object after 3 seconds \n" );
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Algebra.Com's Answer #176888 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! The height about the ground of an object t seconds after it is launched vertically upward is h(t)=100t-5t^2 meters \n" ); document.write( "What is the velocity of the object after 3 seconds \n" ); document.write( "--------------- \n" ); document.write( "h'(t) = 100 - 10t \n" ); document.write( "h'(3) = 70 m/sec \n" ); document.write( "----------------- \n" ); document.write( "Did you mean to ask the height? If so, \n" ); document.write( "h(3) = 100*3 - 5*9 \n" ); document.write( "h(3) = 255 meters, going up at 70 meters/sec \n" ); document.write( " |