document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=241462>Question 241462</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 6e^(2x)-16e^x=6\r<BR>\n" );
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document.write( "solve for x.  please explain </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #176854 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=176854\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 6e^(2x)-16e^x=6<BR>\n" );
document.write( "3e^2x - 8e^x - 3 = 0<BR>\n" );
document.write( "It's a quadratic in e^x.  You can sub y for e^x if it makes it clearer.<BR>\n" );
document.write( "--> y^2 - 8y - 3 = 0<BR>\n" );
document.write( "I'll just do it with e^x<BR>\n" );
document.write( "(3e^x + 1)*(e^x - 3) = 0<BR>\n" );
document.write( "e^x = 3<BR>\n" );
document.write( "x = ln(3)<BR>\n" );
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document.write( "e^x = -1/3  Ignore this one, no exponent will give a negative (in real numbers)<BR>\n" );
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