document.write( "Question 241437: peggy is 4 and rose is 10
\n" ); document.write( "drowzerz: in how many yrs
\n" ); document.write( " will rose be twice as old as peggy?
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Algebra.Com's Answer #176834 by josmiceli(19441)\"\" \"About 
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Let \"n\" = the number of years from now when
\n" ); document.write( "Rose will be twice as old as Peggy
\n" ); document.write( "\"4+%2B+n\" will be Peggy's age then
\n" ); document.write( "\"10+%2B+n\" will be Rose's age then
\n" ); document.write( "given:
\n" ); document.write( "\"10+%2B+n+=+2%2A%284+%2B+n%29\"
\n" ); document.write( "\"10+%2B+n+=+8+%2B+2n\"
\n" ); document.write( "Subtract \"8\" from both sides
\n" ); document.write( "\"2+%2B+n+=+2n\"
\n" ); document.write( "\"n+=+2\"
\n" ); document.write( "In 2 years, Rose will be twice as old as Peggy
\n" ); document.write( "check:
\n" ); document.write( "\"10+%2B+n+=+2%2A%284+%2B+n%29\"
\n" ); document.write( "\"10+%2B+2+=+2%2A%284+%2B+2%29\"
\n" ); document.write( "\"12+=+2%2A6\"
\n" ); document.write( "\"12+=+12\"
\n" ); document.write( "OK
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