document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=241369>Question 241369</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of two numbers is 70. The second is 10 more than 3 times the first. Find the numbers. Choose the answer with the correct equations used to solve this problem. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #176773 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=176773\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The sum of two numbers is 70. The second is 10 more than 3 times the first. Find the numbers. Choose the answer with the correct equations used to solve this problem.<BR>\n" );
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document.write( "Equations:<BR>\n" );
document.write( "x + y = 70<BR>\n" );
document.write( "y = 3x+10<BR>\n" );
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document.write( "Subsitute for \"y\" and solve for \"x\":<BR>\n" );
document.write( "x + (3x+10) = 70<BR>\n" );
document.write( "4x = 60<BR>\n" );
document.write( "x = 15 (1st number)<BR>\n" );
document.write( "y = 3x+10, so y = 45*10 = 55 (2nd number)<BR>\n" );
document.write( "==========================================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( " </SPAN>\n" );
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