document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=241348>Question 241348</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the soultion to the system of equations. \r<BR>\n" );
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document.write( "8x - 5y = 31 <BR>\n" );
document.write( "x - 4y = 14 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #176754 by </B><A HREF=/tutors/aboutme.mpl?userid=unlockmath><B>unlockmath(1688)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=unlockmath><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=unlockmath><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=176754\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hello, <BR>\n" );
document.write( "There's two to solve this. Let's do substitution method. We can get x alone in the second equation so it looks like:<BR>\n" );
document.write( "x = 14+4y   Now use this in the first equation to look like:<BR>\n" );
document.write( "8(14+4y)-5y = 31  Combine like terms gives us:<BR>\n" );
document.write( "112 + 27y=31  Subtract 112 from both sides gives us:<BR>\n" );
document.write( "27y=-81   Divide both sides by 27 gives us:<BR>\n" );
document.write( "y=-3  Now we can find x using either original equation. <BR>\n" );
document.write( "8x - 5(-3) = 31<BR>\n" );
document.write( "8x-15=31<BR>\n" );
document.write( "x=2   Plug these into the original equation and it should come out good.<BR>\n" );
document.write( "RJ Toftness<BR>\n" );
document.write( "www.math-unlock.com<BR>\n" );
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