document.write( "Question 241289: sqrt(8a^9)/b^3 = (8a^9)(b^3)
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\n" ); document.write( " = (8a^3)(b^3)\r
\n" ); document.write( "\n" ); document.write( " = 8ab^3\r
\n" ); document.write( "\n" ); document.write( "Is this correct? I am not sure I am following the steps correctly in this formula? \r
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Algebra.Com's Answer #176702 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
your equation is:\r
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\n" ); document.write( "\n" ); document.write( "\"sqrt%288a%5E9%29%2Fb%5E3+=+%288a%5E9%29%2A%28b%5E3%29\"\r
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\n" ); document.write( "\n" ); document.write( "since b^3 * b^3 = b^(3+3), then multiply both sides of equation by b^3 to get:\r
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\n" ); document.write( "\n" ); document.write( "\"sqrt%288a%5E9%29+=+%288a%5E9%29%2A%28b%5E6%29\"\r
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\n" ); document.write( "\n" ); document.write( "divide both sides of your equation by b^9 to get:\r
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\n" ); document.write( "\n" ); document.write( "\"%28sqrt%288a%5E9%29%29+%2F+%288a%5E9%29+=+%28b%5E6%29\"\r
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\n" ); document.write( "\n" ); document.write( "since sqrt(8a^9)^2 = 8a^9, and (8a^9)^2 = 64a^18, and (b^6)^2 = b^12, then square both sides of your equation to get:\r
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\n" ); document.write( "\n" ); document.write( "\"%288a%5E9%29+%2F+%2864a%5E18%29+=+%28b%5E12%29\"\r
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\n" ); document.write( "\n" ); document.write( "since 8/64 = 1/8, and a^9 / a^18 = a^(9-18) = a^(-9) = 1/a^9, then perform the indicated operations to get:\r
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\n" ); document.write( "\n" ); document.write( "\"%281%2F%288a%5E9%29%29+=+%28b%5E12%29\"\r
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\n" ); document.write( "\n" ); document.write( "if you are solving for b, then you will get:\r
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\n" ); document.write( "\n" ); document.write( "\"b+=+root%2812%2C%281%2F%288a%5E9%29%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "if you are solving for a, then you will get:\r
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\n" ); document.write( "\n" ); document.write( "\"a+=+root%289%2C%28%281%2Fb%5E12%29%2F8%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "I confirmed the answer is good by letting a = 2.\r
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\n" ); document.write( "\n" ); document.write( "This made b = .5\r
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\n" ); document.write( "\n" ); document.write( "You can confirm for yourself by using any number for a and then solving for b.\r
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\n" ); document.write( "\n" ); document.write( "conversely you can use any number for b and then solve for a.\r
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\n" ); document.write( "\n" ); document.write( "either way, the answers should be able to be plugged into the original equation to confirm that the values are good.\r
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