document.write( "Question 241234: Could someone please help me with this mixture problem? I have been pouring over it for two days (total of over 4 hours), and have tried various methods none of them yielding the correct answer.
\n" ); document.write( "A mechanic has 363 gallons of gasoline and 17 gallons of oil to make gas/oil mixtures. He wants one mixture to be 6% oil and the other mixture to be 2.5% oil. If he wants to use all of the gas and oil, how many gallons of gas and oil are in each of the resulting mixtures?
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Algebra.Com's Answer #176699 by edjones(8007)\"\" \"About 
You can put this solution on YOUR website!
Let x=gals of gas required to make a .025 mixture.
\n" ); document.write( "Let y=gals of oil required to make a .025 mixture.
\n" ); document.write( ".
\n" ); document.write( "A) y/(x+y)=.025
\n" ); document.write( "B) (17-y)/(363-x+17-y)=.06
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\n" ); document.write( "A)
\n" ); document.write( "y=.025x+.025y
\n" ); document.write( ".975y=.025x
\n" ); document.write( "y=.0256x
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\n" ); document.write( "B)
\n" ); document.write( "(17-.0256x)/(380-x-.0256x)=.06
\n" ); document.write( "17-.0256x=22.8-.0615x
\n" ); document.write( ".0359x=5.8
\n" ); document.write( "x=161.56 gal
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\n" ); document.write( "A)
\n" ); document.write( "y/(161.56+y)=.025
\n" ); document.write( "y=4.039+.025y
\n" ); document.write( ".975y=4.039
\n" ); document.write( "y=4.142 gal
\n" ); document.write( "It wont be exact because of rounding errors.
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\n" ); document.write( "Ed
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