document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=241259>Question 241259</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how long will it take for $1000 to grow to $42,900 at an interest rate of 10.6% if the intrest is compounded continuously? Round the number of years to the nearest hundredth.\r<BR>\n" );
document.write( "\n" );
document.write( "i got 35.46 years and 3546.11 years\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "which is correct? :) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #176676 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=176676\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> how long will it take for $1000 to grow to $42,900 at an interest rate of 10.6% if the intrest is compounded continuously? Round the number of years to the nearest hundredth. <BR>\n" );
document.write( "-----------------------<BR>\n" );
document.write( "A(t)=Pe^(rt)<BR>\n" );
document.write( "42,900 = 1000*e^(0.106t)<BR>\n" );
document.write( "Divide by 1000 to get:<BR>\n" );
document.write( "e^0.106t = 42.9<BR>\n" );
document.write( "Take the natural log to get:<BR>\n" );
document.write( "0.106t = 3.75887..<BR>\n" );
document.write( "t = 35.46 years<BR>\n" );
document.write( "=========================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );