document.write( "Question 241175: Reconciling remainders. Find a positive integer smaller
\n" ); document.write( "than 500 that has a remainder of 3 when divided by 5, a
\n" ); document.write( "remainder of 6 when divided by 9, and a remainder of 8
\n" ); document.write( "when divided by 11.
\n" ); document.write( "

Algebra.Com's Answer #176662 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
Reconciling remainders.
\n" ); document.write( "Find a positive integer smaller than 500 that has a remainder of 3 when divided by 5,
\n" ); document.write( " a remainder of 6 when divided by 9, and a remainder of 8 when divided by 11.
\n" ); document.write( ":
\n" ); document.write( "we know
\n" ); document.write( "x = multiple of 5 + 3, last digit is either 3 or 8
\n" ); document.write( "x = multiple of 9 + 6
\n" ); document.write( "x = multiple of 11 + 8,
\n" ); document.write( ":
\n" ); document.write( "Find a multiple of 11 + 8, last digit is 3 or 8
\n" ); document.write( "then test to see if it is a multiple of 9 with a remainder 6
\n" ); document.write( ":
\n" ); document.write( "working downward from 500, I came up with 393
\n" ); document.write( "(I used the table on the TI83, with the equation y = 11x + 8, look for last digit of 3 or 8)
\n" ); document.write( ":
\n" ); document.write( "393/5 = 78 r3
\n" ); document.write( "393/9 = 43 r6
\n" ); document.write( "393/11= 35 r8
\n" ); document.write( ":
\n" ); document.write( "There is probably a neater way of doing this but I can't come up with it
\n" ); document.write( "
\n" ); document.write( "
\n" );