document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=241251>Question 241251</A>: <I><SPAN STYLE=\"word-break: break-all;\"> i do not understant how to answer this question could i get help please. i need to determine how many years it will take for the two accounts to reach the same balance. 1000 investment with a rate of 5.25% compounded continuously and 800 investment with a rate of 6.25% compounded continously. i got this far\r<BR>\n" );
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document.write( "1000e^.0525=800e^.0625 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #176653 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=176653\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> how many years it will take for the two accounts to reach the same balance. 1000 investment with a rate of 5.25% compounded continuously and 800 investment with a rate of 6.25% compounded continously. i got this far <BR>\n" );
document.write( "1000e^.0525=800e^.0625<BR>\n" );
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document.write( "1000e^.0525t=800e^.0625t You need the time in the exponents<BR>\n" );
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document.write( "Take the ln of both sides<BR>\n" );
document.write( "ln(1000) + 0.0525t = ln(800) + 0.0625t<BR>\n" );
document.write( "0.0625t - 0.0525t = ln(1000) - ln(800)<BR>\n" );
document.write( "0.01t =~ 0.223144<BR>\n" );
document.write( "t =~ 22.3144 years (assuming the int rates are annual)<BR>\n" );
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