document.write( "Question 241186: please help me solve this\r
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document.write( "log (6x+5) - log (3) = log (2) - log (x) \n" );
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Algebra.Com's Answer #176624 by solver91311(24713)![]() ![]() You can put this solution on YOUR website! \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Presuming equal bases:\r \n" ); document.write( "\n" ); document.write( "1. The sum of the logs is the log of the product.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "2. The difference of the logs is the log of the quotient.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "3. If the logs are equal, the arguments are equal.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Solve the quadratic. The quadratic does not factor over the rationals, so you will need to use the quadratic formula. (or complete the square, if you prefer -- though I would recommend against it in this case). You must then exclude any root that would cause either of the log arguments containing the variable to be negative.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "John \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |