document.write( "Question 240762: Solve for b:\r
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document.write( "logb8=-3 \n" );
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Algebra.Com's Answer #176590 by JimboP1977(311) You can put this solution on YOUR website! b^(-3) = 8 \n" ); document.write( "(b^(-3))^(-1/3) = 8^-1/3 \n" ); document.write( "b^(-3*-1/3) = 8^-1/3 \n" ); document.write( "b^1 = 0.5 \n" ); document.write( " |