document.write( "Question 30904: Two cars start together and travel in the same direction, one going twice as fast as the other. At the end of 3 hours, they are 96 miles apart. How fast is each car traveling? \n" ); document.write( "
Algebra.Com's Answer #17658 by mbarugel(146)\"\" \"About 
You can put this solution on YOUR website!
Hello!
\n" ); document.write( "The previous solution you got for this question (\"The fast car is travelling at 21 and 1/3 miles an hour\", etc) is actually incorrect.\r
\n" ); document.write( "\n" ); document.write( "Let's call X to the the speed of the faster car, and Y to the speed of the other one, both measured in miles per hour. After 3 hours, the fast car has traveled a distance of 3X miles, and the slow car has traveled a distance of 3Y miles.\r
\n" ); document.write( "\n" ); document.write( "Now, since they are 96 miles apart, the equation that describes this is:\r
\n" ); document.write( "\n" ); document.write( "\"3X+-+3Y+=+96+\"\r
\n" ); document.write( "\n" ); document.write( "The other equation (\"one going twice as fast as the other\") is:\r
\n" ); document.write( "\n" ); document.write( "\"X+=+2Y\"
\n" ); document.write( "[recall that X is the fast car]\r
\n" ); document.write( "\n" ); document.write( "So we have the system:
\n" ); document.write( "\"system%283X+-+3Y+=+96+%2CX+=+2Y%29\"\r
\n" ); document.write( "\n" ); document.write( "Substituting the 2nd equation into the 1st one, we get:\r
\n" ); document.write( "\n" ); document.write( "\"3%282Y%29+-+3Y+=+96\"
\n" ); document.write( "\"6Y+-+3Y+=+96\"
\n" ); document.write( "\"3Y+=+96\"
\n" ); document.write( "\"Y+=+32\"\r
\n" ); document.write( "\n" ); document.write( "So the slow car is traveling at 32 mph, and the fast car is traveling at 64 mph.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "I hope this helps!\r
\n" ); document.write( "\n" ); document.write( "Get more answers at Online Math Answers.com!
\n" ); document.write( "
\n" ); document.write( "
\n" );