document.write( "Question 241099: (n+2)!/n!=56
\n" ); document.write( "where n=N\r
\n" ); document.write( "\n" ); document.write( "my answer: n= 7\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

Algebra.Com's Answer #176577 by vleith(2983) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"%28n%2B2%29%21%2Fn%21+=+56\"$
\n" ); document.write( " $\"%28n%2B2%29%21+=+56+%2A+n%21\"$
\n" ); document.write( " $\"%28n%2B2%29%28n%2B1%29n%21+=+56+%2An%21\"$ }
\n" ); document.write( " $\"%28n%2B2%29%28n%2B1%29+=+56\"$
\n" ); document.write( " $\"n%5E2+%2B+3n+-54+=+0\"$
\n" ); document.write( " $\"%28n%2B9%29%28n-6%29+=+0\"$
\n" ); document.write( "So n = -9 or n=6\r
\n" ); document.write( "\n" ); document.write( "Since n=-9 is not possible in n!, then it must be n=6
\n" ); document.write( "Which makes sense since n+1=7 and n+2=8 and 7*8 = 56 \n" ); document.write( "

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