document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=241093>Question 241093</A>: <I><SPAN STYLE=\"word-break: break-all;\"> what is the answer and explation of x=6y-4,x=-2y+28 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #176576 by </B><A HREF=/tutors/aboutme.mpl?userid=unlockmath><B>unlockmath(1688)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=unlockmath><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=unlockmath><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=176576\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hello, <BR>\n" );
document.write( "We can attack this problem from a couple different ways so let's take the easy route. Let's multiply the second equation by 3.(I'm doing this so the y cancels)Also note when you multiply everything needs to be multiplied.<BR>\n" );
document.write( "(3)x=(3)-2y+(3)28 or 3x=-6y+84<BR>\n" );
document.write( "x=6y-4<BR>\n" );
document.write( "3x=-6y+84   Now we can add both equations together which will give us:<BR>\n" );
document.write( "4x=80  Divide both sides by 4<BR>\n" );
document.write( "x=20   Plug this answer into the original equation (either equation will work)<BR>\n" );
document.write( "20=6y-4  Add 4 to both sides<BR>\n" );
document.write( "24=6y  Divide both sides by 6<BR>\n" );
document.write( "4=y    There we go plug these answers y=4 and x=20 into both equations and it should work out. <BR>\n" );
document.write( "RJ Toftness<BR>\n" );
document.write( "www.math-unlock.com </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );