document.write( "Question 240679: 1. A line passes through (2, –1) and (8, 4).\r
\n" ); document.write( "\n" ); document.write( "a. Write an equation for the line in point-slope form.
\n" ); document.write( "b. Rewrite the equation in standard form using integers.
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Algebra.Com's Answer #176568 by ankor@dixie-net.com(22740)\"\" \"About 
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1. A line passes through (2, –1) and (8, 4).
\n" ); document.write( "Find the slope using the slope formula: m = \"%28y2-y1%29%2F%28x2-x1%29\"
\n" ); document.write( "Assign these as follows
\n" ); document.write( "x1=2; y1=-1
\n" ); document.write( "x2=8; y2=4
\n" ); document.write( ":
\n" ); document.write( "m = \"%284-%28-1%29%29%2F%288-2%29\" = \"%284%2B1%29%2F%288-2%29\" = \"5%2F6\" is the slope
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\n" ); document.write( "a. Write an equation for the line in point-slope form.
\n" ); document.write( "The point-slope form: y - y1 = m(x - x1)
\n" ); document.write( "y - (-1) = \"5%2F6\"(x - 2)
\n" ); document.write( "y + 1 = \"5%2F6\"x - \"5%2F6\"*2
\n" ); document.write( "y + 1 = \"5%2F6\"x - \"5%2F3\"
\n" ); document.write( "y = \"5%2F6\"x - \"5%2F3\" -1
\n" ); document.write( "y = \"5%2F6\"x - \"5%2F3\" - \"3%2F3\"
\n" ); document.write( ":
\n" ); document.write( "y = \"5%2F6\"x - \"8%2F3\"; is the point-slope form
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\n" ); document.write( "b. Rewrite the equation in standard form using integers.
\n" ); document.write( "y = \"5%2F6\"x - \"8%2F3\"
\n" ); document.write( "Multiply each term by 6 to get rid of the denominators, results
\n" ); document.write( "6y = 5x - 2(8)
\n" ); document.write( "6y = 5x - 16
\n" ); document.write( "-5x + 6y = - 16
\n" ); document.write( "They prefer the 1s term to be positive, multiply by -1
\n" ); document.write( "5x - 6y = 16
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\n" ); document.write( ":
\n" ); document.write( "You can check our equation:
\n" ); document.write( "substitute 8 for x and 4 for y and ensure they = 16
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