document.write( "Question 30898: A man has a daughter and a son.
\n" ); document.write( "The son is three years older than the daughter.
\n" ); document.write( "In 17 years the son will be twice as old as the daughter is now.
\n" ); document.write( "What is the daughter's present age?
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Algebra.Com's Answer #17656 by Paul(988)\"\" \"About 
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Son's age = 3+x
\n" ); document.write( "Daugther's age = x
\n" ); document.write( "In 17 years son's age = x+17+3-->x+20\r
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\n" ); document.write( "\n" ); document.write( "Equation:
\n" ); document.write( "2(x)=x+20
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2x=x+20
\n" ); document.write( "x=20\r
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\n" ); document.write( "\n" ); document.write( "20+3=23
\n" ); document.write( "Hence, the age for the son is 23 years and the age for the dauther is 20 years.
\n" ); document.write( "Paul.
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