document.write( "Question 30898: A man has a daughter and a son.
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document.write( "The son is three years older than the daughter.
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document.write( "In 17 years the son will be twice as old as the daughter is now.
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document.write( "What is the daughter's present age? \n" );
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Algebra.Com's Answer #17656 by Paul(988)![]() ![]() ![]() You can put this solution on YOUR website! Son's age = 3+x \n" ); document.write( "Daugther's age = x \n" ); document.write( "In 17 years son's age = x+17+3-->x+20\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Equation: \n" ); document.write( "2(x)=x+20 \n" ); document.write( "2x=x+20 \n" ); document.write( "x=20\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "20+3=23 \n" ); document.write( "Hence, the age for the son is 23 years and the age for the dauther is 20 years. \n" ); document.write( "Paul. \n" ); document.write( " \n" ); document.write( " |