document.write( "Question 241075: the length of a rectangle is 5 meters less than twice its width.If the perimeter of the rectangle is 38 meters, then what is the value of the length(in meters) \n" ); document.write( "
Algebra.Com's Answer #176547 by checkley77(12844)\"\" \"About 
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L=2W-5
\n" ); document.write( "2L+2W=38
\n" ); document.write( "2(2W-5)+2W=38
\n" ); document.write( "4W-10+2W=38
\n" ); document.write( "6W=38+10
\n" ); document.write( "6W=48
\n" ); document.write( "W=48/6
\n" ); document.write( "W=8 ANS. FOR THE WIDTH.
\n" ); document.write( "L=2*8-5
\n" ); document.write( "L=16-5
\n" ); document.write( "L=11 ANS. FOR THE LENGTH.
\n" ); document.write( "PROOF:
\n" ); document.write( "2*11+2*8=38
\n" ); document.write( "22+16=38
\n" ); document.write( "38=38
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