document.write( "Question 241072: Please solve for x - thankyou
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Algebra.Com's Answer #176545 by Edwin McCravy(20086)\"\" \"About 
You can put this solution on YOUR website!
\"2%2Broot%283%2C13x-11-3x%5E2%29+=+x\"
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document.write( "Isolate the cube root:\r\n" );
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document.write( "\"root%283%2C13x-11-3x%5E2%29+=+x-2\"\r\n" );
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document.write( "Raise both sides to the 3rd power (that is, \"cube\" both sides)\r\n" );
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document.write( "\"%28root%283%2C13x-11-3x%5E2%29%29%5E3+=+%28x-2%29%5E3\"\r\n" );
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document.write( "Raising a radical to the same exponent as its index amounts\r\n" );
document.write( "to removing the radical and the exponent, so we have:\r\n" );
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document.write( "\"13x-11-3x%5E2+=+%28x-2%29%5E3\"\r\n" );
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document.write( "But we must multiply the right side out:\r\n" );
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document.write( "\"13x-11-3x%5E2+=+%28x-2%29%28x-2%29%28x-2%29\"\r\n" );
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document.write( "\"13x-11-3x%5E2+=+%28x%5E2-4x%2B4%29%28x-2%29\"\r\n" );
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document.write( "\"13x-11-3x%5E2+=+x%5E3-2x%5E2-4x%5E2%2B8x%2B4x-8\"\r\n" );
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document.write( "\"13x-11-3x%5E2+=+x%5E3-6x%5E2%2B12x-8\"\r\n" );
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document.write( "Get 0 on one side:\r\n" );
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document.write( "\"0=x%5E3-3x%5E2-x%2B3\"\r\n" );
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document.write( "We like the 0 to be on the right, so we switch sides:\r\n" );
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document.write( "\"x%5E3-3x%5E2-x%2B3=0\"\r\n" );
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document.write( "Factor \"x%5E2\" out of the first two terms on the left:\r\n" );
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document.write( "\"x%5E2%28x-3%29-x%2B3=0\"\r\n" );
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document.write( "Factor \"-1\" out of the last two terms on the left:\r\n" );
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document.write( "\"x%5E2%28x-3%29-1%28x-3%29=0\"\r\n" );
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document.write( "Factor \"%28x-3%29\" out of both terms on the left:\r\n" );
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document.write( "\"%28x-3%29%28x%5E2-1%29=0\"\r\n" );
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document.write( "Factor the second parentheses as the difference of sqwuares:\r\n" );
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document.write( "\"%28x-3%29%28x-1%29%28x%2B1%29=0\"\r\n" );
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document.write( "Use the zero-factor principle and set each factor = 0:\r\n" );
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document.write( "x-3=0 gives solution x=3\r\n" );
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document.write( "x-1=0 gives solution x=1\r\n" );
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document.write( "x+1=0 gives solution x=-1\r\n" );
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document.write( "The solutions are -1, 1, and 3.  They all check in the original.\r\n" );
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document.write( "(You only need to check radical equations for extraneous solutions\r\n" );
document.write( "when there is a root with an even index or a denominator containg\r\n" );
document.write( "a variable.)\r\n" );
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document.write( "Edwin
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