document.write( "Question 240732: The stopping distance of (s) of a car varies directly as the square of it's speed (v). If a car traveling at 30 mph requires 63 ft to stop, find the stopping distance for a car traveling at 50 mph.\r
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Algebra.Com's Answer #176544 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! The stopping distance of (s) of a car varies directly as the square of it's speed (v). \n" ); document.write( "If a car traveling at 30 mph requires 63 ft to stop, \n" ); document.write( ": \n" ); document.write( "find the stopping distance for a car traveling at 50 mph. \n" ); document.write( "s = stopping dist at 50 mph \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( "cross multiply \n" ); document.write( "900s = 63*2500 \n" ); document.write( "s = \n" ); document.write( "s = 175 ft \n" ); document.write( " |