document.write( "Question 241000: If a pharmacist needs 70L of a 50% alchohol solution but only has a 30% alchohol solution and a 80% alchohol solution how many L of each would make a 50% solution? \n" ); document.write( "
Algebra.Com's Answer #176525 by stanbon(75887)\"\" \"About 
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If a pharmacist needs 70L of a 50% alchohol solution but only has a 30% alchohol solution and a 80% alchohol solution how many L of each would make a 50% solution?
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\n" ); document.write( "Equation:
\n" ); document.write( "alcohol + alcohol = alcohol
\n" ); document.write( "0.30x + 0.80(70-x) = 0.50*70
\n" ); document.write( "Multiply thru by 100 to get:
\n" ); document.write( "30x + 80*70 - 80x = 50*70
\n" ); document.write( "-50x = -30*70
\n" ); document.write( "x = 42 L (amt. of 30% solution needed in the mixture)
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\n" ); document.write( "70-42 = 28 L (amt. of 80% solution needed in the mixture)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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