document.write( "Question 30904: Two cars start together and travel in the same direction, one going twice as fast as the other. At the end of 3 hours, they are 96 miles apart. How fast is each car traveling? \n" ); document.write( "
Algebra.Com's Answer #17652 by aussie7us(3)\"\" \"About 
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This can be solved algebrically. You have two equations.
\n" ); document.write( "1- \"2X=Y\" where x is the speed of the first car, and y is the speed of the second (faster) car.
\n" ); document.write( "2- \"3x%2B3y=96\" 96 is their distance away from each other, and the 3's stand for the hours. car X has traveled for three hours, and so has car Y.
\n" ); document.write( " Next work out the equation. You can use substitution.
\n" ); document.write( "\"+3x%2B3%282Y%29=96\" distribute
\n" ); document.write( "then
\n" ); document.write( "\"3x%2B6x=96\" add like terms
\n" ); document.write( "then
\n" ); document.write( "\"9x=96\" divide both sides by 9 \"9x%2F9=96%2F9\"
\n" ); document.write( "\"x=10%2B2%2F3\" so car x (slow car) is traveling at 10 and 2/3 miles an hour.
\n" ); document.write( "Now, plug the X value into equation 1 \"2X=Y\"
\n" ); document.write( "The fast car is travelling at 21 and 1/3 miles an hour.
\n" ); document.write( "\"Y=10%2B2%2F3\"
\n" ); document.write( " You can also check your answer. Plug in both numbers into equation 2. You get
\n" ); document.write( "\"3%2810%2B2%2F3%29%2A+%2821%2B1%2F3%29=96%29\" if this equation is true, then your answers are correct.
\n" ); document.write( "(it is true)
\n" ); document.write( "HOPE THIS HELPS!
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