document.write( "Question 240956: 2. Suppose that the width of a rectangle is three feet shorter than length and that the perimeter of the rectangle is 84 feet.
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document.write( "a) Set up an equation for the perimeter involving only L, the length of the rectangle.
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document.write( "Answer:
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document.write( "b) Solve this equation algebraically to find the length of the rectangle. Find the width as well.
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document.write( " Answer: Length 22.5, Width 19.5
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document.write( " Show your work here:W=L-3
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document.write( "2W+2L=84
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document.write( "2(L-3)+2L=84
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document.write( "2L-6+2L=84
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document.write( "4L=84+6
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document.write( "4L=90
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document.write( "L=90/4
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document.write( "L=22.5 ANS. FOR THE LENGTH.
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document.write( "W=22.5-3=19.5 ANS. FOR THE WIDTH.
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document.write( "PROOF:
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document.write( "2*19.5+2*22.5=84
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document.write( "39+45=84
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document.write( "84=84
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document.write( " \n" );
document.write( "
Algebra.Com's Answer #176508 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! W=L-3 \n" ); document.write( "2W+2L=84 \n" ); document.write( "2(L-3)+2L=84 \n" ); document.write( "2L-6+2L=84 \n" ); document.write( "4L=84+6 \n" ); document.write( "4L=90 \n" ); document.write( "L=90/4 \n" ); document.write( "L=22.5 ANS. FOR THE LENGTH. \n" ); document.write( "W=22.5-3=19.5 ANS. FOR THE WIDTH. \n" ); document.write( "PROOF: \n" ); document.write( "2*19.5+2*22.5=84 \n" ); document.write( "39+45=84 \n" ); document.write( "84=84 \n" ); document.write( " |