document.write( "Question 240964: Give that the polynomial function has the given zero, find the other zeros.
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Algebra.Com's Answer #176507 by Edwin McCravy(20056)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "\"f%28x%29=x%5E3-3x%5E2-5x%2B39\"\r\n" );
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document.write( "-3 | 1 -3 -5  39\r\n" );
document.write( "   |   -3 18 -39\r\n" );
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document.write( "     1 -6 13   0\r\n" );
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document.write( "So now you have factored the \r\n" );
document.write( "polynomial f(x) this far:\r\n" );
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document.write( "\"f%28x%29=%28x%2B3%29%28x%5E2-6x%2B13%29\"\r\n" );
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document.write( "The zeros are found by setting\r\n" );
document.write( "this equal to 0:\r\n" );
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document.write( "\"%28x%2B3%29%28x%5E2-6x%2B13%29=0\"\r\n" );
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document.write( "\"x%2B3=0\" give the zero -3 which was given.\r\n" );
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document.write( "\"x%5E2-6x%2B13=0\" will give the other zeros.\r\n" );
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document.write( "But this will not factor so we must use the\r\n" );
document.write( "quadratic formula:\r\n" );
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document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\" \r\n" );
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document.write( "with \"a=1\", \"b=-6\", and \"c=13\"\r\n" );
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document.write( "\"x+=+%28-%28-6%29+%2B-+sqrt%28%28-6%29%5E2-4%2A%281%29%2A%2813%29+%29%29%2F%282%2A%281%29%29+\"\r\n" );
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document.write( "\"x+=+%286+%2B-+sqrt%2836-52+%29%29%2F2+\"\r\n" );
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document.write( "\"x+=+%286+%2B-+sqrt%28-16%29%29%2F2+\"\r\n" );
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document.write( "\"x+=+%286+%2B-+i%2Asqrt%2816%29%29%2F2+\"\r\n" );
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document.write( "\"x+=+%286+%2B-+i%2A4%29%2F2+\"\r\n" );
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document.write( "\"x+=+%286+%2B-+4i%29%2F2+\"\r\n" );
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document.write( "\"x+=+6%2F2+%2B-+4i%2F2+\"\r\n" );
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document.write( "\"x+=+3+%2B-+2i+\" \r\n" );
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document.write( "The other zeros are \"3%2B2i\" and \"3-2i\"\r\n" );
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document.write( "Edwin
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