document.write( "Question 240847: you inherit $13000.00 and decide to invest the money in two different investments; one paying 10% and the other 14%. a year later they earn $1580. how much do you originally invewst in each account. \n" ); document.write( "

Algebra.Com's Answer #176465 by checkley77(12844) $\"\"$ $\"About$

You can put this solution on YOUR website!
.14x+.10(13,000-x)=1,580
\n" ); document.write( ".14x+1,300-.10x=1,580
\n" ); document.write( ".04x=1,580-1,300
\n" ); document.write( ".04x=280
\n" ); document.write( "x=280/.04
\n" ); document.write( "x=7,000 amount invested @ 14%.
\n" ); document.write( "13,000-7,000=6,000 amount invested @ 10%.
\n" ); document.write( "Proof:
\n" ); document.write( ".14*7,000+.10*6,000=1,580
\n" ); document.write( "980+600=1,580
\n" ); document.write( "1,580=1,580 \n" ); document.write( "

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