document.write( "Question 240807: log 8 (sqrt 8^9) = n \n" ); document.write( "
Algebra.Com's Answer #176414 by jsmallt9(3759)\"\" \"About 
You can put this solution on YOUR website!
\"log%288%2C+%28sqrt%288%5E9%29%29%29+=+n\"
\n" ); document.write( "As usual, there are several ways to solve this. Maybe the quickest way is based on
  • knowing our exponents (including fractional exponents) well
  • seeing that the argument of the base 8 logarithm is a power of 8
  • knowing that you do not need a calculator to find the base 8 logarithm of a power of 8

\n" ); document.write( "Since square roots are the same as raising to the 1/2 power we can rewrite the argument:
\n" ); document.write( "\"log%288%2C+%28%288%5E9%29%5E%281%2F2%29%29%29+=+n\"
\n" ); document.write( "Using the property of exponents, \"%28a%5Ep%29%5Eq+=+a%5E%28p%2Aq%29\", we get:
\n" ); document.write( "\"log%288%2C+%288%5E%289%2F2%29%29%29+=+n\"
\n" ); document.write( "Using the property of logarithms, \"log%28a%2C+%28p%5Eq%29%29+=+q%2Alog%28a%2C+%28p%29%29\", we can move the exponent out in front:
\n" ); document.write( "\"%289%2F2%29log%288%2C+%288%29%29+=+n\"
\n" ); document.write( "Since by definition \"log%28a%2C+%28a%29%29+=+1\":
\n" ); document.write( "\"9%2F2+=+n\"
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