document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=240740>Question 240740</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a certain rectangle is 3 cm greater than its width. If the width were doubled and the length were decreased by 1 cm, the new rectangle would have the same perimeter as the original. Find the dimensions of the original rectangle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #176412 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=176412\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> L=w+3<BR>\n" );
document.write( "P=2(w+w+3)=4w+6 replace L with w+3<BR>\n" );
document.write( ".<BR>\n" );
document.write( "2nd rectangle:<BR>\n" );
document.write( "2w<BR>\n" );
document.write( "L-1=w+2<BR>\n" );
document.write( "2(2w+w+2)=4w+6<BR>\n" );
document.write( "6w+4=4w+6<BR>\n" );
document.write( "2w=2<BR>\n" );
document.write( "w=1 cm, L=4 cm<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Ed </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );