document.write( "Question 240804: PLEASE HELP SOLVE THIS CIRCULAR FUNCTIONS AND THEIR GRAPHS:
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document.write( "What is the phase shift of F(x)=3 sin (2x-4)?
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document.write( "HERE ARE THE POSSIBLE ANSWERS:
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document.write( "a)2 right
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document.write( "b)2 left
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document.write( "c)4 right \n" );
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Algebra.Com's Answer #176411 by jsmallt9(3758)![]() ![]() ![]() You can put this solution on YOUR website! For sin and cos, if you write the equation in the form: \n" ); document.write( " \n" ); document.write( "or \n" ); document.write( " \n" ); document.write( "The numbers you find for A, B, C and D will tell you a lot about the function: \n" ); document.write( "A = the amplitude. \n" ); document.write( "B = \n" ); document.write( "C = the vertical shift \n" ); document.write( "D = the horizontal (or phase shift) \n" ); document.write( "Your equation is almost in the right form. We just need to factor the 2 in the argument: \n" ); document.write( " \n" ); document.write( "Now we can \"read\" the equation: \n" ); document.write( "A = 3 so the amplitude is 3. \n" ); document.write( "B = 2 so we could use \n" ); document.write( "C is missing so it is zero. There is no vertical shift. \n" ); document.write( "D = 2 so the horizontal or phase shift is 2 (to the right). (A negative D would be a shift to the left.) \n" ); document.write( " |